<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:georss='http://www.georss.org/georss'><id>tag:blogger.com,1999:blog-1280924050178911268</id><updated>2009-11-27T22:52:12.552+01:00</updated><title type='text'>matematicamedie</title><subtitle type='html'></subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><link rel='next' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default?start-index=26&amp;max-results=25'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>572</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>25</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-5300234442464820389</id><published>2009-11-27T17:47:00.001+01:00</published><updated>2009-11-27T17:47:19.786+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='segmenti'/><category scheme='http://www.blogger.com/atom/ns#' term='geogebra'/><category scheme='http://www.blogger.com/atom/ns#' term='enti geometrici fondamentali'/><category scheme='http://www.blogger.com/atom/ns#' term='linee'/><title type='text'>Linee, segmenti, coppie di segmenti</title><summary type='text'>Ragazzi, I!  per chi riesce: tempo, connessioni e varie…  cominciate a vedere i due lavori seguenti.  Linea, linea retta e segmento. Clic sull’immagine, istruzioni sulla finestra applet:Coppie di segmenti. Clic e istruzioni…   Link:  potete anche divertirvi da Maestra Renata, con un bel video,   Robo Tino e le linee, e Geometria: classificare le linee (già segnalato su questo blog… da ritrovare!:</summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/5300234442464820389/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=5300234442464820389' title='4 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/5300234442464820389'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/5300234442464820389'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/linee-segmenti-coppie-di-segmenti.html' title='Linee, segmenti, coppie di segmenti'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>4</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-7137216911748541953</id><published>2009-11-26T19:05:00.001+01:00</published><updated>2009-11-26T19:05:50.248+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='circonferenza'/><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni on line'/><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni'/><title type='text'>Esercizionline_02_terza</title><summary type='text'>Giovanotti, :-)  l’esercitazione che qui vi propongo non è una mia creazione, l’ho trovata, gentilmente condivisa da una collega, sul sito dove abbiamo la classe. [Appena abbiamo un po’ di materiali, condivideremo anche noi!]  Fa al caso nostro e perciò, esercitatevi! (clic sotto)  CERCHIO E CIRCONFERENZA    </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/7137216911748541953/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=7137216911748541953' title='3 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/7137216911748541953'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/7137216911748541953'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/esercizionline02terza.html' title='Esercizionline_02_terza'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>3</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-6606567991787913206</id><published>2009-11-25T16:00:00.001+01:00</published><updated>2009-11-25T16:00:58.706+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Immagini per la Matematica'/><category scheme='http://www.blogger.com/atom/ns#' term='matematica ricreativa'/><category scheme='http://www.blogger.com/atom/ns#' term='geogebra'/><title type='text'>Le pale eoliche</title><summary type='text'>Gabriele,  è andato con la sua squadra di calcio a giocare a …  dove, Gabri? :-) Mah, penso verso Porto Torres – Stintino.   Fatto sta che ha visto le pale eoliche, ne è stato colpito e ha deciso di disegnarle con Geogebra. Funzionanti eh?!   Clic sull’immagine, attivare l’animazione o muovere lo slider manualmente.  </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/6606567991787913206/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=6606567991787913206' title='12 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/6606567991787913206'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/6606567991787913206'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/le-pale-eoliche.html' title='Le pale eoliche'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>12</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-4259938744348944015</id><published>2009-11-24T15:29:00.001+01:00</published><updated>2009-11-24T15:29:35.154+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni on line'/><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni'/><category scheme='http://www.blogger.com/atom/ns#' term='Insieme N dei numeri naturali'/><title type='text'>Esercizionline_03_prima</title><summary type='text'>Ragazzi, I!  Ormai passwordmuniti  :-), seguite le indicazioni per l’esecuzione di un nuovo esercizio (lo so, non avete ancora fatto gli altri, non importa: cominciate con questo, ci tengo! – domani abbiamo aritmetica…)   Quando invece vorrete scegliere gli esercizi dalla vostra pagina iniziale leggete le indicazioni date alla III!  Dopo aver cliccato sull’immagine sotto [Esercizio sull’insieme N</summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/4259938744348944015/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=4259938744348944015' title='6 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/4259938744348944015'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/4259938744348944015'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/esercizionline03prima.html' title='Esercizionline_03_prima'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-2369941605891961189</id><published>2009-11-24T14:49:00.001+01:00</published><updated>2009-11-24T14:49:22.164+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='esercizi sui triangoli'/><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni on line'/><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni'/><title type='text'>Esercizionline_01_terza</title><summary type='text'>Ragazzi,  Ecco la vostra pagina iniziale. Avete ora le password, dopo aver cliccato sull’immagine sotto, scegliete il vostro nome dal menu a tendina, immettete la password, OK. Vi apparirà l’elenco degli esercizi (per ora è uno) da eseguire. Cliccate sul nome dell’esercizio (Test Name), in una nuova finestra potrete procedere, clic su Start testing.   Una volta date le risposte, o anche una per </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/2369941605891961189/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=2369941605891961189' title='7 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/2369941605891961189'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/2369941605891961189'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/esercizionline01terza.html' title='Esercizionline_01_terza'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-5975170999445480762</id><published>2009-11-23T10:45:00.005+01:00</published><updated>2009-11-23T23:55:46.407+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='esercizi sui triangoli'/><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni on line'/><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni'/><title type='text'>Esercizionline_02_prima</title><summary type='text'>Ragazzi,
ecco un esercizio di geometria. Chiamiamolo ancora test-allenamento: nessuna valutazione! Clic sull’immagine
</summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/5975170999445480762/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=5975170999445480762' title='2 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/5975170999445480762'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/5975170999445480762'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/esercizionline02prima.html' title='Esercizionline_02_prima'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-6784876936460105831</id><published>2009-11-22T16:51:00.001+01:00</published><updated>2009-11-23T19:17:21.911+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Segnalazioni'/><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni on line'/><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni'/><category scheme='http://www.blogger.com/atom/ns#' term='divisione'/><title type='text'>Altra bella sorpresa…</title><summary type='text'>Ragazzi (entrambe le classi!)  prima di ogni cosa, guardate QUI!   Come ho detto da maestra Renata, potevo mai privare voi di tale opportunità? :-)  Ho creato così anch’io le vostre “classi in rete”!  Avete la possibilità di eseguire vari esercizi on line, che via via preparerò per voi, e potrò poi controllare i risultati, che vedrò solo io, tranquilli! Fornirò a ciascuno di voi la propria </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/6784876936460105831/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=6784876936460105831' title='12 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/6784876936460105831'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/6784876936460105831'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/altra-bella-sorpresa.html' title='Altra bella sorpresa…'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>12</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-2412125587732415236</id><published>2009-11-22T12:10:00.001+01:00</published><updated>2009-11-22T12:10:14.271+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni on line'/><category scheme='http://www.blogger.com/atom/ns#' term='geogebra'/><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni'/><category scheme='http://www.blogger.com/atom/ns#' term='costruzione di triangoli'/><title type='text'>Triangoli SI triangoli NO</title><summary type='text'>Ragazzi,  Ispirata da un lavoro di maestra Renata, Costruzione di triangoli,  ho preparato una esercitazione su GeoGebra.   Utilizzando gli strumenti opportuni siete guidati a costruire dei triangoli. Data la misura dei lati, verificare SE la costruzione è possibile o no e individuare anche il perché.   Clic sulla figura (vedete solo una parte dell’esercizio), leggete con attenzione sul foglio di</summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/2412125587732415236/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=2412125587732415236' title='6 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/2412125587732415236'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/2412125587732415236'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/triangoli-si-triangoli-no.html' title='Triangoli SI triangoli NO'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-6240599936256553509</id><published>2009-11-20T10:59:00.001+01:00</published><updated>2009-11-20T10:59:51.663+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='matematica nella storia'/><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni on line'/><category scheme='http://www.blogger.com/atom/ns#' term='geogebra'/><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni'/><title type='text'>Cerchio_casa!</title><summary type='text'>Gabriele,  riferendosi a questa chiacchierata…  ha realizzato la sua costruzione con GeoGebra.  Gabri, sfruttando la tua idea di muovere punto e segmento lasciando la traccia … sul foglio dinamico trovi una sorpresa: animazione attiva. Non devi muovere tu! :-)  Bene, ti (vi!) aiuto a scoprire come si fa . Cercate gli strumenti:     Slider    Ruota intorno a un punto di un angolo    Mostra/</summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/6240599936256553509/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=6240599936256553509' title='10 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/6240599936256553509'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/6240599936256553509'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/cerchiocasa.html' title='Cerchio_casa!'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>10</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-3706034855693169541</id><published>2009-11-19T19:11:00.001+01:00</published><updated>2009-11-19T20:28:20.034+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Sistemi di riferimento'/><category scheme='http://www.blogger.com/atom/ns#' term='prodotto cartesiano'/><category scheme='http://www.blogger.com/atom/ns#' term='geogebra'/><category scheme='http://www.blogger.com/atom/ns#' term='Operazioni con gli insiemi'/><category scheme='http://www.blogger.com/atom/ns#' term='Sistema di riferimento cartesiano'/><title type='text'>Il prodotto cartesiano</title><summary type='text'>Nel nostra discussione sugli insiemi, al momento è un fuori programma …  ma Gabriele, che ha frugato sul file del prof. Popinga, dice di non aver compreso bene e ne vuol sapere di più.  Io dico wow! :-) Saranno curiosi anche gli altri? ?  Partiamo dall’osservazione.  Una tabella a doppia entrata:       Un grafico di Eulero-Venn:  Un grafo ad albero:  Secondo me avete già capito…        ma </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/3706034855693169541/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=3706034855693169541' title='3 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/3706034855693169541'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/3706034855693169541'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/il-prodotto-cartesiano.html' title='Il prodotto cartesiano'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>3</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-8064148631051001148</id><published>2009-11-18T15:18:00.001+01:00</published><updated>2009-11-18T15:22:35.562+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Excel'/><category scheme='http://www.blogger.com/atom/ns#' term='Operazioni con gli insiemi'/><title type='text'>Intersezione e Unione in Excel</title><summary type='text'>Ragazzi,  vi ricordo il file Excel da scaricare per esercitarvi sulle operazioni di Intersezione e Unione tra insiemi. Ecco due immagini, leggete le indicazioni nei Commenti nella cella. Clic sulla prima immagine per scaricare    E abbiamo ancora un altro file Excel, un regalo del prof. Popinga: Operazioni con gli Insiemi.xls, che oltre alle operazioni di Intersezione e Unione contiene Differenza</summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/8064148631051001148/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=8064148631051001148' title='6 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/8064148631051001148'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/8064148631051001148'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/intersezione-e-unione-in-excel.html' title='Intersezione e Unione in Excel'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-8186327780156528445</id><published>2009-11-18T14:06:00.001+01:00</published><updated>2009-11-18T14:06:01.500+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Immagini per la Matematica'/><title type='text'>Raggi!</title><summary type='text'>O piccoli …  osservate      Matematita - Immagini per la Matematica via kwout      bello, no? la natura è più bella … ! :-)  Sul blog abbiamo altre immagini per la matematica dal sito *Matematita*. Vi invito a cercarle, a visitare il sito e… certo, certo, dovremo visitarlo insieme. Dovremo!  </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/8186327780156528445/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=8186327780156528445' title='0 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/8186327780156528445'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/8186327780156528445'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/raggi.html' title='Raggi!'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-124364705541155708</id><published>2009-11-17T17:39:00.001+01:00</published><updated>2009-11-17T17:41:56.825+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='video'/><category scheme='http://www.blogger.com/atom/ns#' term='rotazione'/><category scheme='http://www.blogger.com/atom/ns#' term='geogebra'/><category scheme='http://www.blogger.com/atom/ns#' term='Tutoriali'/><title type='text'>Rotazione: ancora un “come si fa”</title><summary type='text'>Avevamo visto      Rotazione: individua il centro e...     Ci siamo accorti che occorre un rinforzo per un’altra operazione:  come costruire la figura (F’ ) corrispondente ad un figura (F ) in una rotazione, dati centro di rotazione, ampiezza e verso.  Su carta, sul quaderno, abbiamo visto, occorrono righello e goniometro.   Un filmato, su Geogebra, vi può aiutare a fissare la procedura da </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/124364705541155708/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=124364705541155708' title='4 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/124364705541155708'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/124364705541155708'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/rotazione-ancora-un-come-si-fa.html' title='Rotazione: ancora un “come si fa”'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>4</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-9202455482447636523</id><published>2009-11-17T15:00:00.000+01:00</published><updated>2009-11-17T15:00:02.894+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Analogie di struttura'/><category scheme='http://www.blogger.com/atom/ns#' term='Excel'/><title type='text'>Per la prima: le analogie di struttura</title><summary type='text'>Ragazzi (dico per la classe prima ma mica è male se rivedono i più grandi…!)  a proposito delle tabelle simili per … struttura, vero?  Andate a vedere QUESTO (abbiamo visto intersezione di insiemi e congiunzione logica "e" o "et" latino, oppure AND, simbolo ∧)  e poi   QUESTO  Trovate al primo link un bel file Excel da scaricare! (Per ora non preoccupatevi delle formule, ne parliamo insieme…)  </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/9202455482447636523/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=9202455482447636523' title='0 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/9202455482447636523'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/9202455482447636523'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/per-la-prima-le-analogie-di-struttura.html' title='Per la prima: le analogie di struttura'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-8253276690206114253</id><published>2009-11-14T18:56:00.001+01:00</published><updated>2009-11-14T19:46:59.646+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='matematica nella storia'/><category scheme='http://www.blogger.com/atom/ns#' term='Esercitazioni on line'/><category scheme='http://www.blogger.com/atom/ns#' term='geogebra'/><title type='text'>La forma rotonda!</title><summary type='text'>Con ampia discussione abbiamo sviluppato in classe la nostra storiella!  L’uomo esce dalle caverne, l’uomo si ingegna a costruire, l’uomo inventa la ruota perché gli serve per trasportare carichi… (i ragazzi scriveranno [spero!] la loro cronaca), l’uomo costruisce delle capanne a forma rotonda.  E giù le ipotesi su come ha fatto a tracciare i confini delle primitive abitazioni: “qui ci sarà la </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/8253276690206114253/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=8253276690206114253' title='16 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/8253276690206114253'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/8253276690206114253'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/la-forma-rotonda.html' title='La forma rotonda!'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>16</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-4841838096760398629</id><published>2009-11-14T14:34:00.001+01:00</published><updated>2009-11-14T14:35:43.353+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Carnevale della matematica'/><title type='text'>Carnevale della Matematica_19</title><summary type='text'>E’ uscito oggi il                 Gli studenti di oggi: Carnevale della Matematica #19 via kwout   Raga, ho portato anche voi! :-)  </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/4841838096760398629/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=4841838096760398629' title='0 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/4841838096760398629'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/4841838096760398629'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/carnevale-della-matematica19.html' title='Carnevale della Matematica_19'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-7918320128267244524</id><published>2009-11-13T18:54:00.001+01:00</published><updated>2009-11-13T18:54:37.668+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='matematica nella storia'/><title type='text'>La storia di una grotta.</title><summary type='text'>Ragazzi (della classe prima)  ecco la nuova storiella promessa…  Osservate:   L'immagine che vedete è la riproduzione di una pittura trovata in una grotta della Spagna settentrionale, vicino a Santander, nella caverna di Altamira.  La zona rossa dell’immagine      Sapete di che epoca è il disegno? È di 15 o 20 mila anni fa!         In molte zone, soprattutto della Spagna e della Francia, si sono </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/7918320128267244524/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=7918320128267244524' title='3 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/7918320128267244524'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/7918320128267244524'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/la-storia-di-una-grotta.html' title='La storia di una grotta.'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>3</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-4808194610303739481</id><published>2009-11-12T18:11:00.001+01:00</published><updated>2009-11-12T18:13:44.614+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Immagini per la Matematica'/><category scheme='http://www.blogger.com/atom/ns#' term='Dante Alighieri'/><category scheme='http://www.blogger.com/atom/ns#' term='geogebra'/><title type='text'>Dante e …geogebra!</title><summary type='text'>Quella spiritosa di Sara….! :-)    </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/4808194610303739481/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=4808194610303739481' title='6 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/4808194610303739481'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/4808194610303739481'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/dante-e-geogebra.html' title='Dante e …geogebra!'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>6</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-5182931993173547083</id><published>2009-11-11T20:18:00.001+01:00</published><updated>2009-11-12T09:32:06.077+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Poligoni inscritti e circoscritti'/><category scheme='http://www.blogger.com/atom/ns#' term='Attivita laboratoriale'/><category scheme='http://www.blogger.com/atom/ns#' term='geogebra'/><category scheme='http://www.blogger.com/atom/ns#' term='Punti notevoli del triangolo'/><category scheme='http://www.blogger.com/atom/ns#' term='triangoli inscritti e circoscritti'/><title type='text'>Il lampione</title><summary type='text'>Ho proposto ai ragazzi una prova descritta nel   “Quadro di riferimento della matematica - Valutazione dei quindicenni” - OCSE-PISA 2003.   Esempio 1 - IL LAMPIONE      Il consiglio comunale ha deciso di mettere un lampione in un piccolo parco       triangolare in modo che l’intero parco sia illuminato. Dove dovrebbe essere       collocato il lampione?  Ecco una delle relazioni dei ragazzi (tutti</summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/5182931993173547083/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=5182931993173547083' title='12 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/5182931993173547083'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/5182931993173547083'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/il-lampione.html' title='Il lampione'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>12</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-4479506523620145206</id><published>2009-11-10T17:51:00.001+01:00</published><updated>2009-11-10T23:10:51.861+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='matematica e...'/><category scheme='http://www.blogger.com/atom/ns#' term='Attivita laboratoriale'/><category scheme='http://www.blogger.com/atom/ns#' term='conigli di Fiibonacci'/><category scheme='http://www.blogger.com/atom/ns#' term='Successione di Fibonacci'/><title type='text'>I conigli di Fibonacci</title><summary type='text'>E chi li ferma più   i piccini di prima, con le avventure di Fibonacci? :-)  Maria Chiara ci parla del problema dei conigli.  Durante una  gara di matematica Fibonacci risolse in pochissimo tempo un problema  utilizzando la sua famosa successione.  Il testo del problema era così:   C’è una coppia di conigli che si riproduce ogni mese. Ogni nuova coppia si riproduce a sua volta ogni mese , ma a </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/4479506523620145206/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=4479506523620145206' title='7 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/4479506523620145206'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/4479506523620145206'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/i-conigli-di-fibonacci.html' title='I conigli di Fibonacci'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>7</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-3077061368864936193</id><published>2009-11-10T16:06:00.001+01:00</published><updated>2009-11-10T16:06:08.369+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='matematica e...'/><category scheme='http://www.blogger.com/atom/ns#' term='Poligoni inscritti e circoscritti'/><category scheme='http://www.blogger.com/atom/ns#' term='Matematica e poesia'/><category scheme='http://www.blogger.com/atom/ns#' term='Dante Alighieri'/><category scheme='http://www.blogger.com/atom/ns#' term='angoli al centro e angoli alla circonferenza'/><title type='text'>Questo per la III: “o se del mezzo cerchio…”</title><summary type='text'>Ecco, ragazzi  il verso di Dante di cui stamane …  “o se del mezzo cerchio far si pote          triangol sì ch'un retto non avesse.”  PARADISO – canto XIII - Versi 101, 102  si capisce perfettamente, vero?  Traduco tuttavia:     o se nel semicerchio si possa inscrivere un triangolo non rettangolo   In altre parole:  se un triangolo è inscritto in una semicirconferenza, allora necessariamente quel</summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/3077061368864936193/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=3077061368864936193' title='0 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/3077061368864936193'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/3077061368864936193'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/questo-per-la-iii-o-se-del-mezzo.html' title='Questo per la III: “o se del mezzo cerchio…”'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-8685857612540170544</id><published>2009-11-09T12:33:00.001+01:00</published><updated>2009-11-10T18:28:01.322+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='questionari'/><category scheme='http://www.blogger.com/atom/ns#' term='matematica nella storia'/><category scheme='http://www.blogger.com/atom/ns#' term='Sistemi di numerazione'/><category scheme='http://www.blogger.com/atom/ns#' term='sifr'/><category scheme='http://www.blogger.com/atom/ns#' term='Curiosità matematiche'/><title type='text'>Ancora per la “prima”: sullo Zero!</title><summary type='text'>o voi,  che ormai lo chiamate Zephirum e Sunya … che forti siete! :-)  avete letto QUI?  dovete, vi interrogo! eheheh ...  cattivissima :-) :-)  Scherzo naturalmente, ma: c’è una simpatica poesia e troverete la risposta a:  da dove deriva il simbolo grafico "O"?  [pare che…]  Per piacere, provate a rispondere qui sotto:  &amp;ampampampamplt;p&amp;ampampampampgt;Loading...&amp;ampampampamplt;/p&amp;ampampampampgt</summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/8685857612540170544/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=8685857612540170544' title='4 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/8685857612540170544'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/8685857612540170544'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/ancora-per-la-prima-sullo-zero.html' title='Ancora per la “prima”: sullo Zero!'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>4</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-7096715912373212441</id><published>2009-11-07T16:50:00.001+01:00</published><updated>2009-11-07T16:50:09.739+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Segnalazioni'/><category scheme='http://www.blogger.com/atom/ns#' term='presentazioni'/><category scheme='http://www.blogger.com/atom/ns#' term='Insiemi'/><title type='text'>Per la I A … sugli insiemi</title><summary type='text'>Ragazzi,  ora potete andare a vedere la presentazione che cercavamo stamane. CLIC !  Sul sito che vi segnalo qui sotto invece potete trovare teoria ed esercizi (anche con soluzioni!). Trovate il pulsante per scorrere le pagine, scegliete solo ciò che vi interessa! :-) Clic sull’immagine        Insiemi via kwout       Se avete difficoltà scrivete. Ci sono qua io ! :-)  </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/7096715912373212441/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=7096715912373212441' title='10 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/7096715912373212441'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/7096715912373212441'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/per-la-i-sugli-insiemi.html' title='Per la I A … sugli insiemi'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>10</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-2121128101868617315</id><published>2009-11-06T20:21:00.001+01:00</published><updated>2009-11-08T11:46:46.128+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='equiscomponibilità'/><category scheme='http://www.blogger.com/atom/ns#' term='Attivita laboratoriale'/><category scheme='http://www.blogger.com/atom/ns#' term='Funzioni matematiche e funzioni empiriche'/><category scheme='http://www.blogger.com/atom/ns#' term='equiestensione'/><category scheme='http://www.blogger.com/atom/ns#' term='equivalenza di figure piane'/><category scheme='http://www.blogger.com/atom/ns#' term='quarto di cerchio'/><category scheme='http://www.blogger.com/atom/ns#' term='geometria piana'/><category scheme='http://www.blogger.com/atom/ns#' term='geogebra'/><title type='text'>La nostra soluzione del problema del quarto di cerchio</title><summary type='text'>Il problema era questo  E’ stata davvero un’interessante attività.   Ha richiesto diversi incoraggiamenti è vero (ma in questo sta il vero interesse!). Tra un’ipotesi esatta e una errata … siamo giunti a una conclusione.   Riportiamo la figura. Si tratta di riconoscere che la porzione rossa e quella blu della figura hanno la stessa area. Il settore circolare AOB è equivalente a  $\frac{ 1 }{ 4} $</summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/2121128101868617315/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=2121128101868617315' title='4 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/2121128101868617315'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/2121128101868617315'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/la-nostra-soluzione-del-problema-del.html' title='La nostra soluzione del problema del quarto di cerchio'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>4</thr:total></entry><entry><id>tag:blogger.com,1999:blog-1280924050178911268.post-1477135353922009472</id><published>2009-11-06T19:19:00.001+01:00</published><updated>2009-11-06T19:19:09.377+01:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='matematica e...'/><category scheme='http://www.blogger.com/atom/ns#' term='Attivita laboratoriale'/><category scheme='http://www.blogger.com/atom/ns#' term='matematica ricreativa'/><category scheme='http://www.blogger.com/atom/ns#' term='Excel'/><category scheme='http://www.blogger.com/atom/ns#' term='Successione di Fibonacci'/><title type='text'>Per la serie … di Fibonacci!</title><summary type='text'>Le scoperte continuano… Visto che Letizia ha curato (troppo) la formattazione… :-), inserisco l’immagine della sua relazione: E Maria Chiara, Letizia e Gabriele hanno lavorato con Excel. Ecco l’immagine di uno dei lavori:  </summary><link rel='replies' type='application/atom+xml' href='http://matematicamedie.blogspot.com/feeds/1477135353922009472/comments/default' title='Commenti sul post'/><link rel='replies' type='text/html' href='https://www.blogger.com/comment.g?blogID=1280924050178911268&amp;postID=1477135353922009472' title='2 Commenti'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/1477135353922009472'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/1280924050178911268/posts/default/1477135353922009472'/><link rel='alternate' type='text/html' href='http://matematicamedie.blogspot.com/2009/11/per-la-serie-di-fibonacci.html' title='Per la serie … di Fibonacci!'/><author><name>giovanna</name><uri>http://www.blogger.com/profile/07396125739476711377</uri><email>noreply@blogger.com</email><gd:extendedProperty xmlns:gd='http://schemas.google.com/g/2005' name='OpenSocialUserId' value='05050747508630000016'/></author><thr:total xmlns:thr='http://purl.org/syndication/thread/1.0'>2</thr:total></entry></feed>